Final answer:
In an E. coli strain that is lacI- (null mutant for the lacI gene), there would be no repression of the lac operon, leading to constitutive expression of the lacA, lacZ, and lacY genes regardless of lactose presence.
a is correct
Step-by-step explanation:
In E. Coli, the lacI gene produces a repressor that regulates the expression of the lac operon, which includes the genes lacA, lacZ, and lacY. These genes are necessary for the metabolism of lactose. When the lacI gene has a null mutation, indicated by lacI-, it results in the inability to produce the functional repressor protein. Consequently, the lac operon would not be repressed
The correct statement about an E. coli strain that is lacI- would be:
a. There would be no lac operon repression, thus lacA, lacZ and lacY genes would be constitutively expressed regardless of the presence of lactose.
This is because without the repressor, RNA polymerase can freely transcribe the operon, leading to the continuous production of the enzymes required to metabolize lactose.