Answer:
A. (2a - 7)(a + 4).
Explanation:
2a2 + a − 28
= 2a^2 + 8a - 7a - 28
= 2a(a + 4) - 7(a + 4)
The a + 4 is common so we have:
(2a - 7)(a + 4).
A
2a^2 + a -28
Recall: ax^2 + bx + c
a*c = 2*28= 56
sum of factors= +8-7 = 1
multiply of factor= 8*7=56
2a^2 +8a -7a-28
(2a^2 + 8a) - (7a - 28)
2a(a +4) - 7(a + 4)
Therefore
(2a-7)(a+4)
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