Question

The secondary coil of a step-up transformer provides the voltage that operates an electrostatic air filter. The turns ratio of the transformer is 46:1. The primary coil is plugged into a standard 120-V outlet. The current in the secondary coil is 1.8 x 10-3 A. Find the power consumed by the air filter.

Answer 1

9.936 Watt

Step-by-step explanation:

Ns / Np = 46 : 1

Vp = 120 V

Is = 1.8 x 10^-3 A

Ns / Np = Vs / Vp

46 / 1 = Vs / 120

Vs = 5520 V

Power consumed by the air filter = Vs x Is = 5520 x 1.8 x 10^-3 = 9.936 Watt

Answer 2

The power consumed by the air filter is 9.936 watts

Step-by-step explanation:

It is given that, the secondary coil of a step-up transformer provides the voltage that operates an electrostatic air filter.

Turn ratio of the transformer,
`(N_s)/(N_p)=(46)/(1)`

Voltage of primary coil,
`V_p=120\ V`

Current in the secondary coil,
`I_s=1.8* 10^(-3)\ A`

The power consumed by the air filter is :

`P_s=I_s* V_s`...........(1)

For a transformer,
`(N_s)/(N_p)=(V_s)/(V_p)`

So,
`P_s=I_s* ((N_s)/(N_p))* V_p`

`P_s=1.8* 10^(-3)* ((46)/(1))* 120`

`P_s=9.936\ Watts`

So, the power consumed by the air filter is 9.936 watts. Hence, this is the required solution.