Question

Math Solve the equation:-

Answer 1

Hello !

Answer:

`\Large \boxed{\sf y=-27}`

Explanation:

We want to find the value of y that satisfies the following equation :

`\sf (y+1)/(3) -(3y-1)/(6) =5`

First, multiply both sides by 6 :

`\sf 6(\sf (y+1)/(3) -(3y-1)/(6)) =6*5`

Now let's expand the left side :

`\sf 2y+2-(3y-1)=30`

Combine like terms :

`\sf -y+3=30`

Now let's substract 3 from both sides :

`-\sf y+3-3=30-3\\-y=27`

Finally, let's multiply both sides by -1 :

`\boxed{\sf y=-27}`

Have a nice day ;)

Answer 2

y = -27

Explanation:

• Multiply the entire equation by 6

`\sf 6*(y+1)/(3)-6*(3y-1)/(6)=6*5\\\\\\`

2*(y + 1) - (3y - 1 ) = 30

• Multiply (y +1) by 2 and (3y - 1) by (-1)

2y + 2 - 3y + 1 = 30

• Isolate y term by taking the constant term to RHS

2y - 3y = 30 - 2 - 1

• Combine like terms

-y = 27

y = -27