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Identify the equation of the circle that has its center at (-16,30) and passes through the origin

User Sergii
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1 Answer

3 votes

Answer:

(x+16)²+(y-30)²=1156

Explanation:

We have given:

center at (-16,30). It means h = -16 and k=30

and it passes through the origin (0,0)

Thus the radius will be distance between (-16,30) and (0,0)

r=√(-16 - 0)²+(30-0)²

r=√256+900

r²=(√1156)²

r²=1156

Now apply standard equation of circle:

(x-h)²+(y-k)² = r²

(x+16)²+(y-30)²=1156

Thus the equation is (x+16)²+(y-30)²=1156 ....

User Didierc
by
5.4k points
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