76.8k views
4 votes
Suppose that light from a laser with wavelength 633 nm is incident on a thin slit of width 0.500 mm. If the diffracted light projects onto a screen at distance 1.50 m, what is the distance y2 from the center of the diffraction pattern to the dark band with m=2?

User Maow
by
8.2k points

1 Answer

1 vote

Step-by-step explanation:

It is given that,

Wavelength,
\lambda=633\ nm=633* 10^(-9)\ m

Slit width,
a=0.5\ mm=0.0005\ m

Order, m = 2

If the diffracted light projects onto a screen at distance 1.50 m, L = 1.5 m

For the diffraction of light,


y=(m\lambda L)/(a)


y=(2* 633* 10^(-9)* 1.5)/(0.0005)

y = 0.0037 m

So, the distance from the center of the diffraction pattern to the dark band is 0.0037 meters. Hence, this is the required solution.

User Wizart
by
7.0k points