43.2k views
0 votes
Measurements show that 1.0 g of iron (Fe) contains 1.1 x 1022 Fe atoms. How many Fe atoms are in 4.9 g of Fe, which is the total amount of iron in the body of an average adult?

2 Answers

4 votes

Answer:

eeeeeee

Step-by-step explanation:

its 6 x 65 44ge

User Ofek Gila
by
5.4k points
6 votes

Answer : The number of iron atoms present in 4.9 grams of iron are,
5.39* 10^(22)

Explanation : Given,

As we are given that 1.0 grams of iron contains
1.1* 10^(22) iron atoms.

Now we have to determine the number of iron atoms in 4.9 grams.

As, 1.0 gram of iron contains
1.1* 10^(22) iron atoms

So, 4.9 gram of iron contains
(4.9)/(1.0)* 1.1* 10^(22)=5.39* 10^(22) iron atoms

Therefore, the number of iron atoms present in 4.9 grams of iron are,
5.39* 10^(22)

User Tunmee
by
5.1k points