Question

an isosceles triangle has a vertex angle of 21.21 degrees. two sides of the triangle are each 17.91 ft long. whats the area of the triangle

Answer 1

58.025 sq ft

Explanation:

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Answer 2

The area of triangle is
`A=58.02\ ft^(2)`

Explanation:

Let

B -----> the measure of the vertex angle of the isosceles triangle ABC

a and c -----> the two congruent sides of the isosceles triangle ABC

we know that

The area of a triangle applying the law of sines is equal to

`A=(1)/(2)(a)(c)sin(B)`

we have

`a=c=17.91\ ft`

`B=21.21\°`

substitute in the formula

`A=(1)/(2)(17.91)(17.91)sin(21.21\°)`

`A=58.02\ ft^(2)`