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For electric forces we say that "likes repel, unlikes attract," but for the magnetic forces between two parallel current-carrying wires, we can say "likes attract, unlikes repel." To get a feel for the size of the effects, calculate the magnitude of the force per meter (that is, the force on one meter of wire) if I1= I2 = 12 amperes, and the distance between the wires is d = 4 centimeter.

User Kevin Qiu
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Answer:


7.2\cdot 10^(-4) N/m

Step-by-step explanation:

The magnetic force between two current-carrying wires is given by:


(F)/(L)=(\mu_0 I_1 I_2)/(2\pi r)

where


\mu_0 is the vacuum permeability

I1 and I2 are the two currents

r is the distance between the wires

Here we have:


I_1 = I_2 = 12 A\\r = 4 cm = 0.04 m

Substituting into the equation,


(F)/(L)=((4\pi \cdot 10^(-7))(12)(12))/(2\pi (0.04))=7.2\cdot 10^(-4) N/m

User Babken Vardanyan
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