Question

Complete the following conversions between SI units.

(a) 612 g = _____________mg
(b) 8.160 m= ____________cm
(c) 3779 µg= ____________g
(d) 781 mL = ____________L
(e) 4.18 kg = ____________g
(f) 27.8 m =_____________km
(g) 0.13 mL=____________L
(h) 1738 km = ___________m
(i) 1.9 Gg= _____________g

Answer 1

For a:
`612g=6.12* 10^5mg`

For b: 8.160 m = 816.0 cm

For c:
`3779\mu g=3.779* 10^(-3)g`

For d: 781 mL = 0.781 L

For e: 4.18 kg = 4180 g

For f: 27.8 m = 0.0278 km

For g:
`0.13mL=1.3* 10^(-4)L`

For h:
`1738km=1.738* 10^6m`

For i:
`1.9Gg=1.9* 10^9g`

Step-by-step explanation:

Units is defined as the standard which is used to make comparisons between the measurements.

For the given options:

• For a:

The conversion factor used is:

`1g=1* 10^(3)mg`

So,
`612g* (10^3mg)/(1g)=6.12* 10^5mg`

• For b:

The conversion factor used is:

`1m=100cm`

So,
`8.160m* (100cm)/(1m)=816.0cm`

• For c:

The conversion factor used is:

`1g=1* 10^(6)\mu g`

So,
`3779\mu g* (1g)/(10^6\mu g)=3.779* 10^(-3)g`

• For d:

The conversion factor used is:

`1L=1000mL`

So,
`781mL* (1L)/(1000mL)=0.781L`

• For e:

The conversion factor used is:

`1kg=1000g`

So,
`4.18kg* (1000g)/(1kg)=4180g`

• For f:

The conversion factor used is:

`1km=1000m`

So,
`27.8m* (1km)/(1000m)=0.0278km`

• For g:

The conversion factor used is:

`1L=1000mL`

So,
`0.13mL* (1L)/(1000mL)=1.3* 10^(-4)L`

• For h:

The conversion factor used is:

`1km=1000m`

So,
`1738km* (1000m)/(1km)=1.738* 10^6m`

• For i:

The conversion factor used is:

`1Gg=10^9g`

So,
`1.9Gg* (10^9g)/(1Gg)=1.9* 10^9g`

Answer 2

a) 612000 mg

b) 816 cm

c) 3.779 E-7 g

d) 0.781 L

e) 4180 g

f) 0.0278 Km

g) 1.3 E-4 L

h) 1738000 m

i) 1900000000 g

Step-by-step explanation:

a) 612 g * ( 1000mg / g ) = 612000 mg

b) 8.160 m * ( 100 cm / m ) = 816 cm

c) 3779µg * ( 0.0001 µg /  ) * ( g / 1000000 µg ) = 3.779 E-7 g

d) 781 mL * ( L / 1000 mL) = 0.781 L

e) 4.18 Kg * ( 1000g / Kg) = 4180 g

f) 27.8 m * ( Km / 1000 m ) = 0.0278 Km

g) 0.13 mL * ( L / 1000mL ) = 1.3 E-4 L

h) 1738 Km * ( 1000 m / Km ) = 1738000 m

i) 1.9 Gg * ( 1 E9 g / Gg ) = 1900000000 g