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25 votes
What is the value of 4(x-2)(x-3)+7(x-2)(x-5)+7(x-3)(x-5) when x=3

User Naijaba
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1 Answer

22 votes
22 votes

Answer:

-14

Explanation:

4(x-2)(x-3)+7(x-2)(x-5)+7(x-3)(x-5)

Let x =3

Find the value when x=3

4(x-2)(x-3)+7(x-2)(x-5)+7(x-3)(x-5)

Substitute x=3

4(3-2)(3-3)+7(3-2)(3-5)+7(3-3)(3-5)

Add and subtract inside the parentheses

4(1)(0)+7(1)(-2)+7(0)(-2)

Multiply

0 -14 +0

Add and Subtract

-14

User Nevus
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