Question

A place from this table is chosen at random. let event A= the place is a city

Answer 1

There are 7 places shown in the table which are , →{Rome, Tokyo, Houston, Peru, Miami, Toronto, Canada}

Out of which 5 are cities.

City={Rome, Tokyo, Houston,Miami, Toronto,}=5

It is given that a,place from the city is chosen.

Probability of an Event

`=\frac{\text{Total Favorable event}}{\text{Total possible outcome}}`

Probability of selecting a city from 7 places in which 5 are cities

`P(A)=\frac{_(1)^(5)\textrm{C}}{_(1)^(7)\textrm{C}}\\\\P(A)=(5)/(7)\\\\P(A^c)=1-P(A)\\\\=1-(5)/(7)\\\\=(2)/(7)`

Option B

Answer 2

5/7 is the correct answer

Explanation:

The probability of the place is at city are:

The total probability of the place is at city / The total possible outcomes

= 5 / 7

Hope this help you :3