Question

Below is a graph that represents the total profits for a third month. Write the equation of the line that represents this graph. Show your work or explain how you determined the equations.

Answer 1

`y=-(2)/(3)x +300`

Explanation:

y=mx+b

we have two points

point A=(0,300)

point B=(450,0)

slope=m=
`(y_(2)-y_(1))/(x_(2)-x_(1))`

m=
`(0-300)/(450-0)`

m=-2/3

we need to find "b"

using point A=(0,300), we have

300=0+b

b=300

finally we have

`y=-(2)/(3)x +300`