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how much force does it take to push a 62.0 kg dresser at a constant speed across a carpet with µk=0.238. (unit=N)
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how much force does it take to push a 62.0 kg dresser at a constant speed across a carpet with µk=0.238. (unit=N)

User Yo Ludke
by
4.9k points

2 Answers

1 vote

Answer:

158.76504N

Step-by-step explanation:

F = µk * m * g

F = 0.238 * 62 * 9.81

F = 158.76504N

User ScayTrase
by
3.9k points
5 votes

Answer:

Force, F = 144.6 N

Step-by-step explanation:

It is given that,

Mass of the dresser, m = 62 kg

Coefficient of kinetic friction,
\mu_k=0.238

We need to find force with which the dresser is pushed. It is given by :


F=\mu mg


F=0.238* 62* 9.8

F = 144.6 N

So, the force taken by the dresser is 144.6 N. Hence, this is the required solution.

User Itamar
by
4.5k points
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