Question

"A 0.200-T magnetic field is directed perpendicular to the plane of a circular loop of radius 0.500 m. What is the magnitude of the magnetic flux through the loop?"

Answer 1

Magnetic flux through the loop is 0.25 Weber.

Step-by-step explanation:

It is given that,

Magnetic field, B = 0.2 T

Radius of circular loop, r = 0.5 m

Magnetic field is directed perpendicular to the plane of a circular loop,
`\theta'=90`

Using the formula of magnetic flux as :

`\phi=BA\ cos\theta`

`\phi=BA\ cos(90-\theta)`

`\phi=BA\ sin(90)`

`\phi=0.2* \pi (0.2)^2`

`\phi=0.025\ Wb`

So, the magnitude of the magnetic flux through the loop is 0.25 Weber. Hence, this is the required solution.