Question

5. Thickness measurements of ancient prehistoric Native American pot shards discovered in a Hopi village are approximately normally distributed, with a mean of 5.1 millimeters (mm) and a standard deviation of 0.7 mm. What percent (%) of ancient prehistoric Native American pot shards discovered in this area has thickness measurement thinner than 3.

Answer 1

percent (%) of ancient prehistoric thinner than 3 is 0.0013

Explanation:

Given data

mean = 5.1 millimeters (mm)

standard deviation = 0.7 mm

to find out

percent (%) of ancient prehistoric thinner than 3

solution

we have given mean and SD

so Z will be = x -mean / SD

Z = ( x - 5.1 ) / 0.7

so P( x < 3 ) = P ( (x - 5.1 ) / 0.7 < ( 3 - 5.1 ) / 0.7 )

P( Z = ( 3 - 5.1 ) / 1.5 )

P( Z = -3 ) = 0.0013

percent (%) of ancient prehistoric thinner than 3 is 0.0013