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The function f is defined by

f : x ↦8 - (x - 3)^2
For

2 \leqslant x \leqslant 7
Find the range of f.

Please also explain, since I don't understand, thanks a lot.






1 Answer

3 votes

Answer:

f : x - 8 - [x-3 ]^2 ; f:x ↦8

and 2<x<7

x = 0,1,2

you can put all in the result to have the explaination

User LonelySoul
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