Question

According to the following reaction: KHP+ NaOH> NaKP+ H20 used instead of glucose? water? Sea water? What is the concentration of the NaOH if it took 42.52 ml to titrate 0.835 g of KHP? (MM KHP 204.2 g/mol)

Answer 1

Answer: The molarity of NaOH solution is 0.096 M.

Step-by-step explanation:

To calculate the number of moles, we use the equation:

`\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}`

Given mass of KHP = 0.835 g

Molar mass of KHP = 204.2 g/mol

Putting values in above equation, we get:

`\text{Moles of KHP}=(0.835g)/(204.2g/mol)=0.00408mol`

For the given chemical reaction:

`KHP+NaOH\rightarrow NaKP+H_2O`

By Stoichiometry of the reaction:

1 mole of KHP reacts with 1 mole of NaOH.

So, 0.00408 moles of KHP will react with =
`(1)/(1)* 0.00408=0.00408mol` of NaOH.

To calculate the molarity of NaOH, we use the equation:

`\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}`

We are given:

Moles of NaOH = 0.00408 moles

Volume of solution = 42.52 mL = 0.04252L (Conversion factor: 1L = 1000 mL)

Putting values in above equation, we get:

`\text{Molarity of NaOH }=(0.00408mol)/(0.04252L)=0.096M`

Hence, the molarity of NaOH solution is 0.096 M.