Question

From a group of 8 people, including George and Nina, 3 people are to be selected at random to work on a certain project. What is the probability that the 3 people selected will include George but not Nina?

Answer 1

Answer:
`(15)/(56)`

Explanation:

We have to select george but not nina with two other people

No. of ways selecting 2 two people knowing Geroge will be the third one is

`^6C_2` (beacuse we have to exclude Nina)

And total no of ways of selecting 3 people out of 8 people is
`^8C_3`

Therefore the required Probability is
`(^6C_(2))/(^8C_(3))`

=
`(15)/(56)`