Question

Please I need like an explanation of how it was done.

Find the value of y so that the line passing through (9, 0) and (3, y) has a slope of -1/2

Answer 1

y=3

Explanation:

When a line is said to pass from two sets of points say (x1,y1) and (x2,y2),the slope of the line is given by,

Slope,=(y2-y1)/(x2-x1)

Here, x1=9,x2=3,y1=0,y2=y

Given,slope=-1/2

So,slope=(y-0)/(3-9)=-1/2

or,y/-6=-1/2

or,2y=6

or,y=3 [ANS]

Answer 2

the point is (3, 3) . . . . . . y = 3

Explanation:

Write the point-slope equation of the line through the point you know. Then evaluate that equation for x=3 to see what the value of y is.

Point-slope form:

y = m(x -h) +k . . . . slope m through point (h, k)

y = -1/2(x -9) +0 . . . . line with slope -1/2 through point (9, 0)

For x=3, the value of y is ...

y = -1/2(3 -9) + 0 = -1/2(-6) = 3

The value of y is 3.