Answer:
Part a)
![t = 206.8 nm](https://img.qammunity.org/2020/formulas/physics/college/gyqisg9lwwyfpbmy1dy38a3rnswr5mama2.png)
Part b)
![t = 248.3 nm](https://img.qammunity.org/2020/formulas/physics/college/jj3vxpfiyosiyldvy0u8txb0glhlcgk7n2.png)
Step-by-step explanation:
Part a)
As we know that when light incident on the water layer then for least reflection of light then path difference of two reflected light is equal to the odd multiple of half of wavelength of light
so here we have
![2\mu t - (\lambda)/(2) = (\lambda)/(2)](https://img.qammunity.org/2020/formulas/physics/college/ympucuwn7ksrs6fyedsv773upsczlagebx.png)
![2(1.33)t = 550 nm](https://img.qammunity.org/2020/formulas/physics/college/k9sodwji2diqmvwh7z2ox6hf3y1wk2wdgw.png)
![t = 206.8 nm](https://img.qammunity.org/2020/formulas/physics/college/gyqisg9lwwyfpbmy1dy38a3rnswr5mama2.png)
Part b)
As we know that when light incident on the water layer then for maximum reflection of light then path difference of two reflected light is equal to the integral multiple of wavelength of light
so here we have
![2\mu t = \lambda](https://img.qammunity.org/2020/formulas/physics/college/265ejnat6uc3u2q0woscmn813qn5pu8r4u.png)
![2(1.309)t = 650 nm](https://img.qammunity.org/2020/formulas/physics/college/nuwegi2auu0j882mpfg7wtonwlpzxv90w3.png)
![t = 248.3 nm](https://img.qammunity.org/2020/formulas/physics/college/jj3vxpfiyosiyldvy0u8txb0glhlcgk7n2.png)