Answer:
![6.31* 10^(14)Hz](https://img.qammunity.org/2020/formulas/physics/college/s31dbs7yg8mjzic14nturwunyk7r6nqye5.png)
Step-by-step explanation:
We know that there is a relation between the speed of light ,frequency and wavelength.This relation can be given as
where v is speed of light
is frequency of light
is wavelength of light
In first case we have given λ=655 nm
so using formula
![v=\\u \lambda](https://img.qammunity.org/2020/formulas/physics/middle-school/u2ei9heo2s35i9wjw1w95pw3q0fvdo4omp.png)
![3* 10^8=655* 10^(-9)* \\u](https://img.qammunity.org/2020/formulas/physics/college/7u6lndinrw5i5c4atmw2wn3aqrrpkfudi9.png)
Hz
In second case we have wavelength 515 nm so by using above formula
![3* 10^8=515* 10^(-9)* \\u](https://img.qammunity.org/2020/formulas/physics/college/tqm8otqtn8wxniyk7wni0qgh6dvycywizk.png)
![\\u =5.825* 10^(14)\ Hz](https://img.qammunity.org/2020/formulas/physics/college/37810imbyyvk93nga8n7rez00z323bls5w.png)
In third case we have wavelength 475 nm
so
![3* 10^8=475* 10^(-9)* \\u](https://img.qammunity.org/2020/formulas/physics/college/92rbnkxb0moj3t3s42d37ceivcr3u1hp0p.png)
![\\u =6.31* 10^(14)Hz](https://img.qammunity.org/2020/formulas/physics/college/73vphaalnarrrhj7j6lbmhfkfkkoh73hlm.png)