Question

The fundamental (LaTeX: n=1 n = 1 harmonic or mode) frequency created on a stretched string with fixed ends occurs when the string is driven at a frequency of 50 Hz. If the tension in this string is doubled without changing its mass density, what would be the new fundamental frequency?

Answer 1

Answer:
`√(2)f`

Step-by-step explanation:

Given

Fundamental Frequency(f) is 50 Hz

and frequency is given by

`f=(1)/(2L)\sqrt{(T)/(\mu )}---1`

Where T= tension

`\mu`=mass per unit length

if tension is doubled

`f'=(1)/(2L)\sqrt{(2T)/(\mu )}---2`

Divide 1& 2

`(f)/(f')=\sqrt{(T)/(2T)}`

`f'=√(2)f`