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Consider an ideal gas refrigeration cycle using helium as the working fluid. Helium enters the compressor at 120 kPa and 21°C and compressed to 440 kPa. Helium is then cooled to 16°C before it enters the turbine. Assume constant heat capacity of helium. For a mass flow rate of 0.24 kg/s, the net power input required is:

User Francs
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1 Answer

4 votes

Answer:
W_(net)=103.72 kJ/s

Step-by-step explanation:

Given


P_1=120kPa


T_1=21^(\circ)C\approx 294K


P_2=440kPa


T_3=16^(\circ)C\approx 289 K


T_2 is the compressor exit temperature and is given by


\gamma for helium is
(5)/(3)


C_p for helium is
5.1926 kJ/kg-K


T_2=T_1\left [ (440)/(120)\right ]^(\gamma -1)/(\gamma )


T_2=494.37 K

Now Turbine Exit Pressure is given By


T_4=T_3\left [ (120)/(440)\right ]^(\gamma -1)/(\gamma )


T_4=289\left [ (120)/(440)\right ]^((5)/(3) -1)/((5)/(3))


T_4=171.865 K


W_(net)=mC\left ( \left ( T_2-T_1\right )-\left ( T_3-T_4\right )\right )


W_(net)=0.24* 5.1926\left ( \left ( 494.37-294\right )-\left ( 289-171.865\right )\right )


W_(net)=0.24* 5.1926* 83.235


W_(net)=103.72 kJ/s

User Nivaldo
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