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A toy manufacturer wants to know how many new toys children can buy each year. He thinks the mean is 6.9 toys per year. Assume a previous study found the standard deviation to be 1.3. How large a sample would be required in order to estimate the mean number of toys bought per child at the 98% confidence level with an error at most 0.11 toys?

User SoliQuiD
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1 Answer

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Answer: 758

Explanation:

Given : Mean :
\mu=6.9 \text{ toys per year]

Standard deviation :
\sigma = 1.3

Margin of error :
E=0.11\text{ toys}

Significance level :
\alpha=1-0.98=0.02

Critical value :
z_(\alpha/2)=2.33

Formula for sample size :-


n=((z_(\alpha/2)\sigma)/(E))^2\\\\\Rightarrow\ n=((2.33*1.3)/(0.11))^2=758.251322314\approx758

Hence, the minimum required sample size = 758

User Eloone
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