Question

If a is the average (arithmetic mean) of 6m and 10, b is the average of 4m and 4, and c is the average of 14m and 16, what is the average of a, b, and c in terms of m?

Answer 1

6m+7.5

Explanation:

the arithmetic mean is the average of two numbers

it is given that a is average of 6m and 10

so
`a=(6m+10)/(2)`

b is the average of 4m and 4

so
`b=(4m+4)/(2)`

c is the average of 14m and 16

so
`c=(14m+16)/(2)`

now the average of a ,b and c is given by

`average=(a+b+c)/(3)=((6m+10)/(2)+(4m+4)/(2)+(14m+16)/(2))/(3)=6m+7.5`