Answer: The answer is as follows:
Step-by-step explanation:
Given that,
D(x) =140
![e^(-0.03x)](https://img.qammunity.org/2020/formulas/business/college/bf17xiogn53w6bf4w3w1r9yuvfpxav1td3.png)
Revenue Function, R(x) = x × D(x)
= 140x
![e^(-0.03x)](https://img.qammunity.org/2020/formulas/business/college/bf17xiogn53w6bf4w3w1r9yuvfpxav1td3.png)
For maximizing revenue,
R'(x) = 0
140
+ 140x
×(-0.03) = 0
(140-4.2x) = 0
x =
![(140)/(4.2)](https://img.qammunity.org/2020/formulas/business/college/6zslbuyleixsfbjoyqh4gum4p52jlx8ypk.png)
=
⇒ Number of units sold
Price =
![140e^{-0.03*(100)/(3) }](https://img.qammunity.org/2020/formulas/business/college/xcufh95xppa41o50k8r1pktfs7hxgf6ek6.png)
= 51.50 ⇒ price that will yield the maximum revenue