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What is the temperature of 13.3 moles of carbon dioxide that occupies 6 m3 and applies a pressure of 23 kPa to its container?

User Ranjith V
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1 Answer

3 votes

Answer:

T = 1248 K

Step-by-step explanation:

We can calculate the T, by using the ideal gas law:

PV = nRT

Where we have:

The pressure P, volume V, and temperature T, R is the gas constant, and n is the number of moles of the gas.

According to the international unit systems R is 8.314 J/(K·mol)

With this value the P unit will be Pa and the V unit will be m³.

Then,

T = PV / nR

T = (23 × 1000 × 6) / (13.3 × 8.314)

T = 1248 K

User Jodell
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