Answer:z=0.0768
Explanation:
For Binomial distribution
mean

Where n=90
and probabilty of getting success(P)=0.5 (also q=0.5)



Standard deviation

Now using normal distribution as an approximation to the binomial distribution
![P(x=43)=P\left [ (42.5-45)/(4.743)<z<(43.5-45)/(4.743)\right ]](https://img.qammunity.org/2020/formulas/mathematics/college/chnl8qlgd5bhyl0g46ob5w2d6u66u10n9i.png)
Using standard normal tables P
![\left [ -0.527<z<-0.316 \right ]](https://img.qammunity.org/2020/formulas/mathematics/college/dr1g01t99v0eqguynb23qcxcahddbftx1l.png)
Value z=0.0768