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The weight of a product is measured in pounds. A sample of 50 units is taken from a recent production. The sample yielded X¯¯¯ = 75 lb, and we know that σ2 = 100 lb. Calculate a 99 percent confidence interval for μ.

User Kasheen
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1 Answer

6 votes

Answer: (71.36, 78.64)

Explanation:

Given : Sample size : n= 50

Sample mean :
\overlien{x}=75\text{ lb}

Variance :
\sigma^2=100\text{ lb}

Standard deviation :
\sigma=10\text{ lb}

Significance level :
1-0.99=0.01

Critical value :
z_(\alpha/2)=\pm2.576

The confidence interval for population mean is given by :-


\overline{x}\pm z_(\alpha/2)(\sigma)/(√(n))


=75\pm(2.576)*(10)/(√(50))\\\\\approx75\pm3.64\\\\=(71.36,\ 78.64)

Hence, the 99% confidence interval for population mean
\mu =
(71.36, 78.64)

User Donovan Keating
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