Question

A series circuit has a voltage supply of 12 V and a resistor of 2.4 kΩ. How much power is dissipated by the resistor?

A. 0.005 W
B. 0.06 W
C. 2.4 kW
D. 345.6 kW

Answer 1

(B) 0.06W

Step-by-step explanation:

power absorbed by the resistor is given by
`(V^2)/(R)=I^2R`

Where V = voltage

R= resistance

I = current through the circuit

we have given V =12 Volt and resistance =2.4 K
`\Omega`

current
`I=(V)/(R)=(12)/(2.4* 1000)=5* 10^(-3)A=5mA`

power using voltage and resistance equation

`p=(12^2)/(2.4* 1000)=60mW` =0.06W

using current equation
`P=I^2R=5^2* 12=60mW`= 0.06W