Answer:
0.266 %
Step-by-step explanation:
Distance between Earth and distant planet = 9×10⁹ m
Data rate = 32 Mbps
Frame size = 64 KB = 512 Kbits
Propagation speed = Light speed = 3×10⁸ m/s


Channel utilization rate

∴ The channel utilization if a stop-and-wait protocol is 0.266 %