Question

The area of a rectangular loop of wire is 3.6 × 10-3 m2. The loop is placed in a magnetic field that changes from 0.20 T to 1.4 T in 1.6 s. The plane of the loop is perpendicular to the direction of the magnetic field. What is the magnitude of the induced emf in that loop?

Answer 1

2.7 mV

Step-by-step explanation:

A = 3.6 x 10^-3 m^2

B1 = 0.20 T, B2 = 1.4 T, t = 1.6 s

According to the Faraday's law of electromagnetic induction

e = - rate of change of magnetic flux

e = - dФ / dt

where, negative sign shows the direction of induced emf.

Ф = B x A

dФ / dt = A x dB / dt

e = A x dB / dt = 3.6 x 10^-3 x (1.4 - 0.2) / 1.6

e = 2.7 x 10^-3 V = 2.7 mV