Answer:
x = -7/2 and x = 1
So, there are 2 roots of this equation.
And the roots are real numbers.
Explanation:
We need to describe the nature of roots for this equation
2x^2+5x-7=0
2x^2-2x+7x-7=0
2x(x-1)+7(x-1)=0
(2x+7)(x-1)=0
2x+7=0, x-1=0
2x=-7, x =1
x = -7/2 and x = 1
So, there are 2 roots of this equation.
And the roots are real numbers.