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Which equation describes a reduction?

Mg(s)—Mg2+ (aq) + 2e -
201 + 2e ->201
Na(s) — Nat(aq) + e
Al(s)— A3+ (aq) + 3e -

User Gary Ong
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2 Answers

3 votes

Answer:

1,3,4 equations represent oxidation as charge increases

Your 2 nd option represents reduction

User SooDesuNe
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4 votes

Answer : The reduction will be
X_2+2e^-\rightarrow 2X^-

Explanation :

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In this, oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.

(a) The given half reactions is:


Mg(s)\rightarrow Mg^(2+)(aq)+2e^-

This reaction is an oxidation reaction because in this reaction, the loss of electrons takes place.

(b) The given half reactions is:


X_2+2e^-\rightarrow 2X^-

This reaction is an reduction reaction because in this reaction, the gain of electrons takes place.

(c) The given half reactions is:


Na(s)\rightarrow Na^(+)(aq)+e^-

This reaction is an oxidation reaction because in this reaction, the loss of electrons takes place.

(d) The given half reactions is:


Al(s)\rightarrow Al^(3+)(aq)+3e^-

This reaction is an oxidation reaction because in this reaction, the loss of electrons takes place.

Hence, the reduction will be
X_2+2e^-\rightarrow 2X^-

User Bistaumanga
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