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Let X be a continuous random variable with a uniform distribution on the interval open square brackets 0 comma 10 close square brackets. Find straight P open parentheses straight X less than 1 space or space straight X greater than 8 close parentheses.

User Kisha
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1 Answer

4 votes


X has PDF


f_X(x)=\begin{cases}\frac1{10}&\text{for }0\le x\le10\\0&\text{otherwise}\end{cases}

and thus CDF


F_X(x)=\begin{cases}0&amp;\text{for }x<0\\\frac x{10}&amp;\text{for }0\le x\le10\\1&amp;\text{for }x>10\end{cases}

Because
X is continuous, we have


P(X<1\text{ or }X>8)=1-P(1\le X\le8)=1-(P(X\le8)-P(X\le1))


P(X<1\text{ or }X>8)=1-P(X\le 8)+P(X\le1)


P(X<1\text{ or }X>8)=1-F_X(8)+F_X(1)


P(X<1\text{ or }X>8)=1-\frac8{10}+\frac1{10}=\boxed{\frac3{10}}

User Prabhagaran
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