Answer:
All of the above.
Step-by-step explanation:
In positive deviation from Raoult's Law occur when the vapour pressure of components is greater than what is expected value in Raoult's law.
When a solution is non ideal then it shows positive or negative deviation.
Let two solutions A and B to form non- ideal solutions.let the vapour pressure of component A is
and vapour pressure of component B is
.
= Vapour pressure of component A in pure form
= Vapour pressure of component B in pure form
=Mole fraction of component A
=Mole fraction of component B
The interaction between A- B is less than the interaction A- A and B-B interaction.Therefore, the escaping tendency of liquid molecules in mixture is greater than the escaping tendency in pure form.Hence, the vapour pressure of a mixture is greater than the initial value of vapour pressure.
,
![P_B>P^0_B\cdot x_B](https://img.qammunity.org/2020/formulas/chemistry/college/3tnjt8mrugfp1a3t3pl0pvji8u7s6wge17.png)
Therefore,
![P_A+P_B >P^0_A\cdot x_A+P^0_B \cdot x_B](https://img.qammunity.org/2020/formulas/chemistry/college/dyezvmv5c7awgnvszcsxru8oo9503uc10v.png)
Therefore, the enthalpy of mixing is greater than zero and change in volume is greater than zero.
Hence, option a,b,c and d are true.