Question

Two out of phase loudspeakers are some distance apart. A person stands 4.50 m from one speaker and 3.80 m from the other. What is the third lowest frequency at which the person will hear constructive interference? The speed of sound in air is 347 m/s. Hz

Answer 1

The third lowest frequency is 1489.27 Hz.

Step-by-step explanation:

Given that,

Distance of person from one speaker= 4.50 m

Distance of person from the other = 3.80 m

The longest wavelength is the shortest frequency.

We need to calculate the difference between the speakers

The difference between the speakers d= 4.50-3.80 =0.7 m

We know that,

The longest wavelength is such that one wavelength

`\lambda = d`

So, The third longest wavelength is

`3\lambda=d`

Put the value of d

`\lambda=(0.7)/(3)`

`\lambda=0.233\ m`

We need to calculate the lowest frequency

Using formula of frequency

`f=(v)/(\lambda)`

`f=(347)/(0.233)`

`f=1489.27\ Hz`

Hence, The third lowest frequency is 1489.27 Hz.