Question

Part A What width sit will produce a central maximum that is 2.50 em wide on a screen 2 20 m from the slit? Express your answer to three significant figures Green light (A 558 nm) strikes a single slit at normal incidence

Answer 1

9.82×10⁻² m

Step-by-step explanation:

w = Width of central maximum = 2.5 cm = 0.025 m

D = Distance between screen and slit = 2.2 m

λ = Wavelength of green light = 558 nm = 558×10⁻⁶ m

a = Width of slit

`w=(2\lambda D)/(a)\\\Rightarrow a= (2\lambda D)/(w)\\\Rightarrow a= (2* 558* 10^(-6)* 2.2)/(0.025)\\\Rightarrow a= 98208* 10^(-6)= 9.82* 10^(-2)\ m`

∴ Width of slit is 9.82×10⁻² m