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Assuming a roughly spherical shape and a density of 4000 kg/m3, estimate the diameter of an asteroid having the average mass of 1017 kg.

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Step-by-step explanation:

It is given that,

Density of asteroid,
\rho=4000\ kg/m^3

Mass of asteroid,
m=10^(17)\ kg

We need to find the diameter of the asteroid. The formula of density is given by:


\rho=(m)/(V)

V is the volume of spherical shaped asteroid,
V=(4)/(3)\pi r^3


r^3=(3M)/(4\pi \rho)


r^3=(3* 10^(17)\ kg)/(4\pi * 4000\ kg/m^3)


r^3=\sqrt{5.96* 10^(12)}

r = 2441311.12 m

Diameter = 2 × radius

d = 4882622.24 m

or


d=4.88* 10^6\ m

Hence, this is the required solution.

User Rello
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