Question

At 1 atm pressure, the heat of sublimation of gallium is 277 kJ/mol and the heat of vaporization is 271 kJ/mol. To the correct number of significant figures, how much heat is required to melt 2.50 mol of gallium at 1 atm pressure?

Answer 1

Answer:15 KJ

Step-by-step explanation:

We have given

at 1 atm

The heat of sublimation of Gallium =277 KJ/mol

heat of vaporization of Gallium =271 KJ/mol

`\Delta H=277-271=6KJ/mol`

So heat required to melt 2.50 mol of gallium at 1 atm

Heat Required=
`2.5* 6=15 KJ`

So heat required to melt 2.5 mol of gallium is 15 KJ