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A coin of mass .005 kg dropped from a height of 3 m. How much potential energy does it have right before it hits the ground? Assume there is no air resistance. Acceleration due to gravity is g=9.8 m/s2

User VAndrei
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Final answer:

The potential energy of a 0.005 kg coin dropped from a height of 3 m, right before it hits the ground, can be calculated using the formula PE = mgh. The calculated potential energy is 0.147 joules.

Step-by-step explanation:

To calculate the potential energy of the coin right before it hits the ground, we need to use the formula for gravitational potential energy, which is PE = mgh, where m is the mass, g is the acceleration due to gravity, and h is the height from which the object falls.

In this scenario:

Mass (m) of the coin = 0.005 kg

Acceleration due to gravity (g) = 9.8 m/s²

Height (h) from which the coin is dropped = 3 m

Substituting these values into the formula, we get:

PE = (0.005 kg) × (9.8 m/s²) × (3 m)

PE = 0.147 J

Therefore, the potential energy of the coin right before it hits the ground is 0.147 joules.

User Rubenhak
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