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4 votes
An elastic cord has a spring constant of 38 N/m. How much force is required

to stretch the cord 0.3 m past its natural length?

User Plalx
by
5.3k points

1 Answer

3 votes

Step-by-step explanation:

F = kx

F = (38 N/m) (0.3 m)

F = 11.4 N

Round as needed.

User Hennr
by
5.2k points