Question

Line PQ passes through the points P(-5,-13) and Q(5,17) what is the equation of line PQ in standard form

Answer 1

`3x - y = - 2`

Explanation:

The given line PQ passes through the points P(-5,-13) and Q(5,17) .

Find the slope using the formula:

`m = (y_2-y_1)/(x_2-x_1)`

Plug in the points to get:

`m = (17 - - 13)/(5 - - 5)`

`m = (30)/(10)`

`m = 3`

Use the point-slope formula :

`y-y_1 = m(x - x_1)`

Substitute the point (5,17)

`y - 17 = 3(x - 5)`

Expand:

`y - 17 = 3x - 15`

The standard form is when the equation is put in the form

`ax + by = c`

Regroup the terms to get:

`3x - y = - 17 + 15`

The standard form is

`3x - y = - 2`