The radius of the circle is 11, so the area is
![A=\pi r^2 = 121\pi](https://img.qammunity.org/2020/formulas/mathematics/middle-school/rb5yovv2wln9zt4z3wcpx70fc6s9gvjh7c.png)
The central angles of the shaded and non-shaded regions sum up to 360 degrees, so the central angle of the shaded region is
![360-217=143](https://img.qammunity.org/2020/formulas/mathematics/middle-school/t86doc42bbsrs3l6y7d5hwioud7ic7pkw4.png)
The area of the shaded region is in proportion with the area of the whole circle: if the whole area is given by a sector of 360°, the area of a 143° sector will be given by
![A_(360)/ A_(143) = 360/ 143](https://img.qammunity.org/2020/formulas/mathematics/middle-school/estlsj1fwk6jk524g2y9jjpq4as8mz4yy5.png)
Since we know that the whole area is
, we can solve for the area of the 143° sector:
![121\pi/ A_(143) = 360/ 143 \iff A_(143)=(121\pi\cdot 143)/(360) \approx 151](https://img.qammunity.org/2020/formulas/mathematics/middle-school/v08elsj495dk281gv42vc87hpf21kr3gzk.png)