Question

Factor completely x3 + 4x2 + 8x + 32. (x + 4)(x2 + 8) (x − 4)(x2 − 8) (x − 4)(x2 + 8) (x + 4)(x2 − 8)

Answer 1

`\tt x^3+4x^2+8x+32\\\\=x^2(x+4)+8(x+4)\\\\=\boxed{\tt(x+4)(x^2+8)}`

Answer 2

(x+4)(x^2+8)

Explanation:

x^3 + 4x^2 + 8x + 32

We will factor by grouping

Factor out an x^2 from the first two terms and an 8 from the last two terms

x^2 (x+4) + 8(x+4)

Now we can factor out an (x+4)

(x+4)(x^2+8)