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What is the cube root of 512m12n15
Could anyone plz help me?

What is the cube root of 512m12n15 Could anyone plz help me?-example-1
User Mozammel
by
5.7k points

2 Answers

2 votes

Answer:

C. 8m^4n^5[/tex]

Explanation:

We are given
\sqrt[3]{512m^(12)n^(15)  }

The cube root is nothing but the power of
(1)/(3)

Now we have to write 512 as the power 3.

512 = 8.8.8 =
8^(3)

So,
\sqrt[3]{512m^(12)n^(15)  } =
(8^(3).m^(12).n^(15))   ^{(1)/(3)}

We know that the exponent property:
(a^(m) )^n= a^(mn)

Using this property, we can simplify the exponents.

=
8.m^(4) .n^5 = 8m^4n^5

User Urso
by
5.8k points
4 votes

Answer:


8m^4n^5

Explanation:

cube root is basically taking to the power of
(1)/(3)

Also, there is a property that is
(x^m)^n=x^(mn)

We can use these and find the cube root of the expression:


(512m^(12)n^(15))^{(1)/(3)}\\=(512)^{(1)/(3)}*(m^(12))^{(1)/(3)}*(n^(15))^{(1)/(3)}\\=8*m^{(12)/(3)}*n^{(15)/(3)}\\=8*m^4 * n^5

Thus, third answer chioce is right.

User Trichner
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5.8k points