Answer:
0.5
Explanation:
Sort the given data in ascending order:
47, 48, 50, 52, 53, 53, 55, 68
Possible outlier is number 68. Check whether this number is an outlier:

The interquartile range is

Multiply it by 1.5:

and add to third quartile:

Since
number 68 is an outlier.
The median of the sample with outlier is

The median of the sample without outlier is 52
The difference between the median of the data, including the possible outlier and excluding the possible outlier is 52.5-52=0.5