Position vectors u and v have terminal points of (-6, 3) and (4, -2), respectively. Find the resulting terminal point of 2v - u.
(2, 1)
(14, 1)
(2, -7)
Answer:
(14 , -7)
Explanation:
terminal points: A (-6,3) B (4,-2)
u = x₁ + i y₁ u = -6 + i3
v =x₂ + iy₂ = 4 - i2 2v = 8 - i4
2v - u = (8 - i4) - (-6 + i3) = 14 -i7
Resulting terminal point: (14 , -7)
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