Question

A 50-kg crate is initially at rest on a horizontal floor. A person pushes horizontally with a constant force of 250 N. The maximum static frictional force between the floor and the crate is 275 N. What is the frictional force on the crate while the person pushes on it?

Answer 1

250 N

Step-by-step explanation:

m = Mass of cart = 50 kg

F = Pushing Force = 250 N

g = Acceleration due to gravity = 9.81 m/s²

μ = Coefficient of friction

`F_s =\text{Static frictional force between the floor and the crate}= 275\ N`

N = Weight of cart = mg

N = 50×9.81

N = 490.5 N

`F_s =\mu N\\\Rightarrow \mu=(F_s)/(N)\\\Rightarrow \mu=(275)/(490.5)\\\Rightarrow \mu=0.56`

Here it can be seen that the pushing force is less than the static frictional force so the crate will not move

∴ The frictional force on the crate while the person pushes on it is 250 N